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Question
solve. write your answer in simplest form using integers, fractions, and natural logarithms. 42 = e^x + 1 x =
Step1: Isolate the exponential term
Subtract 1 from both sides of the equation \(42 = e^{x}+1\) to get \(e^{x}=42 - 1\).
\(e^{x}=41\)
Step2: Take the natural logarithm of both sides
Since the exponential function \(y = e^{x}\) and the natural logarithm function \(y=\ln(x)\) are inverse functions, we take the natural logarithm of both sides of \(e^{x}=41\).
Applying \(\ln\) to both sides gives \(\ln(e^{x})=\ln(41)\).
Step3: Simplify the left - hand side
Using the property of logarithms \(\ln(e^{a})=a\) (where \(a = x\) in our case), the left - hand side simplifies to \(x\). So \(x=\ln(41)\)
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\(\ln(41)\)