Question

to solve $e^{4}-3x=\frac{4}{3}x + 9$ by graphing, which equations should be graphed?
$y = 0$
$y=\frac{4}{3}x + 9$
$y=e^{4}-3x-\frac{4}{3}x + 9$
$y=\frac{4}{3}x + 9+e^{4}-3x$
$y=e^{4}-3x$
done

Explanation:

Step1: Recall the method of solving equations by graphing

To solve \(a = b\) by graphing, we graph \(y = a\) and \(y = b\).

Step2: Identify \(a\) and \(b\) in the given equation

In the equation \(e^{4 - 3x}=\frac{4}{3}x + 9\), \(a=e^{4 - 3x}\) and \(b = \frac{4}{3}x+9\).

Answer:

B. \(y=\frac{4}{3}x + 9\), E. \(y=e^{4-3x}\)