Question

sn
express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. for example, he2s²2p² should be entered as he2s^22p^2.

Explanation:

To write the condensed electron configuration of tin (Sn), we first identify its noble - gas core. Tin has an atomic number of 50. The noble gas that precedes tin in the periodic table is krypton (Kr) with an atomic number of 36.
After the noble - gas core [Kr], we fill the remaining orbitals. The remaining electrons are \(50 - 36=14\).
The filling order of orbitals after \(4p\) (the last orbital of Kr) is \(5s\), \(4d\), and \(5p\).
The \(5s\) orbital can hold 2 electrons, the \(4d\) orbital can hold 10 electrons, and the \(5p\) orbital (for tin, we need \(14-(2 + 10)=2\) more electrons)

Answer:

[Kr]5s^24d^105p^2