Question

3
select the correct answer
how many moles of water are produced when 3.25 moles of co₂ are formed during the combustion of methyl alcohol (ch₃oh)?
2ch₃oh + 3o₂ → 2co₂ + 4h₂o
○ a. 1.62 moles
○ b. 3.25 moles
○ c. 6.50 moles
○ d. 13.00 moles

Explanation:

Step1: Determine the mole ratio

From the balanced chemical equation \(2CH_3OH + 3O_2
ightarrow2CO_2 + 4H_2O\), the mole ratio of \(CO_2\) to \(H_2O\) is \(2:4\) or simplified to \(1:2\).

Step2: Calculate the moles of \(H_2O\)

Let \(x\) be the moles of \(H_2O\). Using the mole - ratio, \(\frac{\text{Moles of }CO_2}{\text{Moles of }H_2O}=\frac{1}{2}\). Given moles of \(CO_2 = 3.25\) moles. Then \(x=\frac{4}{2}\times3.25\) (since for every 2 moles of \(CO_2\), 4 moles of \(H_2O\) are produced).

$$x = 2\times3.25=6.50$$

Answer:

C. 6.50 moles