Question

a sealed vessel containing carbon monoxide, carbon dioxide, and oxygen has a total pressure of 2.68 atm. the vessel contains 1.56 atm o₂ and 0.65 atm co₂. what is the partial pressure of carbon monoxide in atm?

Explanation:

Step1: Recall Dalton's Law formula

Total pressure = sum of partial pressures: $P_{\text{total}} = P_{\text{CO}} + P_{\text{CO}_2} + P_{\text{O}_2}$

Step2: Rearrange to solve for $P_{\text{CO}}$

$P_{\text{CO}} = P_{\text{total}} - P_{\text{CO}_2} - P_{\text{O}_2}$

Step3: Substitute values

$P_{\text{CO}} = 2.68 - 0.65 - 1.56$

Step4: Calculate result

$2.68 - 0.65 = 2.03$; $2.03 - 1.56 = 0.47$

Answer:

0.47 atm