Question

a scientist estimates that the mean nitrogen dioxide level in a city is greater than 31 parts per billion. to test this estimate, you determine the nitrogen dioxide levels for 31 randomly selected days. the results (in parts per billion) are listed to the right. assume that the population standard deviation is 11. at α = 0.12, can you support the scientists estimate? complete parts (a) through (e). (a) write the claim mathematically and identify ( h_0 ) and ( h_a ). choose from the following. a. ( h_0: mu = 31 ) ( h_a: mu>31 ) (claim) b. ( h_0: mugeq31 ) (claim) ( h_a: mu<31 ) c. ( h_0: mu<31 ) ( h_a: mugeq31 ) (claim) d. ( h_0: mu = 31 ) (claim) ( h_a: mu>31 ) e. ( h_0: muleq31 ) (claim) ( h_a: mu>31 ) f. ( h_0: muleq31 ) ( h_a: mu>31 ) (claim) (b) find the critical value and identify the rejection region. ( z_0 = 1.17 ) (round to two decimal places as needed.) rejection region: ( z>1.17 ) (c) find the standardized test statistic. ( z=square ) (round to two decimal places as needed.)

Explanation:

Step1: Calculate the sample mean $\bar{x}$

First, sum up all the data values:

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The sample size \(n = 31\). Then \(\bar{x}=\frac{937}{31}\approx30.23\)

Step2: Use the formula for the \(z\) - test statistic

The formula for the \(z\) - test statistic when the population standard deviation \(\sigma\) is known is \(z=\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}}\)

We know that \(\mu = 31\), \(\sigma=11\), and \(n = 31\), \(\bar{x}\approx30.23\)

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Answer:

\(z\approx - 0.39\)