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in science class, richard learns that a substance has a melting point o…

Question

in science class, richard learns that a substance has a melting point of 302 fahrenheit. his teacher asks him to convert this temperature to degrees celsius. what is the melting point of his substance in degrees celsius? 575.6c 150c 486c 185.6*c

Explanation:

Step1: Recall the formula for converting Fahrenheit to Celsius.

The formula to convert Fahrenheit (\(F\)) to Celsius (\(C\)) is \(C=\frac{5}{9}(F - 32)\).

Step2: Substitute the given Fahrenheit value into the formula.

We are given \(F = 302\). Substitute this into the formula:
\(C=\frac{5}{9}(302 - 32)\)

Step3: Simplify the expression inside the parentheses.

First, calculate \(302-32 = 270\). So now we have \(C=\frac{5}{9}\times270\).

Step4: Perform the multiplication.

\(\frac{5}{9}\times270 = 5\times30 = 150\). Wait, no, wait, let's recalculate. Wait, \(270\div9 = 30\), then \(30\times5=150\)? Wait, no, that's wrong. Wait, wait, \(302 - 32 = 270\)? Wait, 302 minus 32 is 270? Wait, 302 - 30 is 272, then minus 2 is 270. Yes. Then \(\frac{5}{9}\times270\). Let's do 270 divided by 9 first: 270 ÷ 9 = 30. Then 30 × 5 = 150? Wait, but the options have 150 as an option. Wait, but let's check again. Wait, maybe I made a mistake. Wait, the formula is \(C=\frac{5}{9}(F - 32)\). So \(F = 302\), so \(302 - 32 = 270\). Then \(\frac{5}{9}\times270\). 270 divided by 9 is 30, 30 times 5 is 150. So \(C = 150\) degrees Celsius. Wait, but let's check with another approach. Wait, maybe I miscalculated. Wait, 302 Fahrenheit to Celsius. Let's use a calculator approach. \(302 - 32 = 270\). \(270\times5 = 1350\). Then \(1350\div9 = 150\). Yes, that's correct. So the Celsius temperature is 150 degrees.

Wait, but wait, the options include 150°C. So that's the correct answer.

Answer:

150°C (corresponding to the option "150°C")