Question

if salt ($5.99 \times 10^{-6}$ mol) is dissolved in $1.50 \times 10^{-2}$ l of water, which expression can be used to find the molarity of the resulting solution?
\bigcirc\\ $2.50 \times 10^{-8}$ m
\bigcirc\\ $2.50 \times 10^{3}$ m
\bigcirc\\ $3.99 \times 10^{-4}$ m
\bigcirc\\ $3.99 \times 10^{4}$ m
done \checkmark

Explanation:

Step1: Recall Molarity Formula

Molarity (\(M\)) is moles of solute divided by liters of solution. Formula: \(M=\frac{\text{moles of solute}}{\text{volume of solution (L)}}\)

Step2: Substitute Values

Given moles \(= 5.99\times10^{-6}\) mol, volume \(= 1.50\times10^{-2}\) L. So \(M=\frac{5.99\times10^{-6}}{1.50\times10^{-2}}\)

Step3: Calculate the Division

Divide the coefficients: \(\frac{5.99}{1.50}\approx3.99\). Divide the exponents: \(10^{-6 - (-2)} = 10^{-4}\). So \(M\approx3.99\times10^{-4}\) M

Answer:

3.99 × 10⁻⁴ M (corresponding to the option "3.99 × 10⁻⁴ M")