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Question
ruling out chance quick check
which statement best describes the randomization distribution created by using the randomized trial data provided below?
response variable mean for treatment groups a and b
| trial # | response variable mean: group a | response variable mean: group b |
|---|---|---|
| 2 | 10.1 | 9.9 |
| 3 | 10.2 | 10.2 |
| 4 | 10.2 | 10.4 |
| 5 | 10.1 | 10.5 |
| 6 | 10.1 | 10.1 |
| 7 | 10.6 | 10.3 |
| 8 | 10.3 | 10.6 |
| 9 | 10.1 | 10.3 |
| 10 | 10.5 | 10.4 |
(7 points)
options (partially visible) about the distribution: center, minimum/maximum values, etc.
Step1: Analyze the data
First, we calculate the overall mean of the response variable. The sum of all means for Group A and Group B across all trials:
For Group A: \(10.5 + 10.1 + 10.2 + 10.2 + 10.1 + 10.1 + 10.6 + 10.3 + 10.1 + 10.5 = 102.7\)
For Group B: \(10.1 + 9.9 + 10.2 + 10.4 + 10.5 + 10.1 + 10.3 + 10.6 + 10.3 + 10.4 = 102.8\)
Total sum: \(102.7+102.8 = 205.5\)
Total number of data points (since each trial has two groups, 10 trials give 20 data points? Wait, no, actually, each trial has Group A and Group B means, so maybe we consider the difference between Group A and Group B means. Let's recast. Let \(d_i=\text{Mean of Group A}-\text{Mean of Group B}\) for each trial \(i\).
Trial 1: \(10.5 - 10.1 = 0.4\)
Trial 2: \(10.1 - 9.9 = 0.2\)
Trial 3: \(10.2 - 10.2 = 0\)
Trial 4: \(10.2 - 10.4 = - 0.2\)
Trial 5: \(10.1 - 10.5 = - 0.4\)
Trial 6: \(10.1 - 10.1 = 0\)
Trial 7: \(10.6 - 10.3 = 0.3\)
Trial 8: \(10.3 - 10.6 = - 0.3\)
Trial 9: \(10.1 - 10.3 = - 0.2\)
Trial 10: \(10.5 - 10.4 = 0.1\)
Now, the randomization distribution is about the difference in means (Group A - Group B). The center of a randomization distribution (when we randomize the groups) should be around 0 (since we are just re - assigning labels, the true difference under the null hypothesis of no treatment effect is 0). The possible values of the difference \(d_i\) range from \(- 0.4\) (Trial 5) to \(0.4\) (Trial 1).
Step2: Evaluate the options
- Option 1: Says the distribution will center on zero (0) with possible values between - 0.4 and + 0.4. This matches our calculation of the differences \(d_i\) (ranging from - 0.4 to 0.4) and the center (expected to be 0 under null hypothesis of no treatment effect).
- Option 2: Centering at 10.3 is incorrect because the randomization distribution is about the difference in means, not the mean of the groups.
- Option 3: The center should be 0, not related to the overall mean of the groups (10.3 is the overall mean? Wait, overall mean of all group means: \(\frac{102.7 + 102.8}{20}\)? No, better to think about the difference. The randomization distribution of the difference should center at 0.
- Option 4: The distribution is about the difference in means, not the means of the groups. The values of the difference range from - 0.4 to 0.4, not the group means (10.1 - 10.6).
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The distribution will center on zero (0) with possible values between - 0.4 and + 0.4 (the first option, assuming the first option is worded as such based on the description).