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Question
rewrite as a logarithmic equation.
$e^{2}=y$
Step1: Recall the exponential - logarithmic conversion formula
The exponential form \(a^{x}=b\) (where \(a > 0,a
eq1\)) can be converted to the logarithmic form \(\log_{a}b=x\). For the natural exponential function, the base \(a = e\), and the natural logarithm is denoted as \(\ln\) (where \(\ln x=\log_{e}x\)).
Given the exponential equation \(e^{2}=y\), comparing with \(a^{x}=b\) (here \(a = e\), \(x = 2\), \(b = y\)).
Step2: Apply the conversion formula
Using the formula for converting exponential to logarithmic form (with base \(e\), so we use the natural logarithm), we get \(\ln y=2\) (since if \(e^{x}=y\), then \(\ln y=x\)).
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\(\ln y = 2\)