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resolver $\frac{b h}{2}=a$ para $b$. $b = \frac{2a}{h}$ resolver 2 litr…

Question

resolver $\frac{b h}{2}=a$ para $b$.
$b = \frac{2a}{h}$
resolver 2 litros + 2 semanas = pag para $w$.
$w=$

Explanation:

  1. For the first - part ($\frac{bh}{2}=A$ and solving for $b$):
  • Explanation:
  • Step 1: Isolate $b$ by multiplying both sides by 2
  • Given $\frac{bh}{2}=A$. Multiply both sides of the equation by 2 to get $bh = 2A$.
  • Step 2: Solve for $b$ by dividing both sides by $h$
  • Since $bh=2A$, then $b=\frac{2A}{h}$ (assuming $h

eq0$).

  1. For the second - part ($2\text{ liters}+2\text{ weeks}$):
  • The units of liters (a measure of volume) and weeks (a measure of time) are not compatible for addition in a standard arithmetic sense. So, the expression $2\text{ liters}+2\text{ weeks}$ is an invalid operation in the context of normal arithmetic. There is no meaningful numerical result for $w$ in the equation $2\text{ liters}+2\text{ weeks}=w$ as these are two different physical quantities.

Answer:

For the first equation, $b = \frac{2A}{h}$ (assuming $h
eq0$). For the second equation, the operation is invalid and no meaningful value for $w$ can be determined.