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regular chemistry name: savannah jackson date: 10/10 class: 4th unit 2 …

Question

regular chemistry
name: savannah jackson date: 10/10 class: 4th
unit 2 - hw 3 -
ws 2: ionic bonding with transition metals and polyatomic ions
make sure you use the criss cross method correctly, and use the naming rules to name correctly.

  • metal names stay the same
  • nonmetals must get the suffix of -ide
  • transition metals (groups 3 - 12) must have roman numerals in their name
  • chromium (ii) → (ii) tells you that this chromium has a +2 charge
  • you can figure out the charge of the transition metal by completing the criss cross method backwards. the subscript on the nonmetal would become the charge for the transition metals
  • polyatomic ions are units, and should not be separated.
  • use your reference sheet to figure out the name or formula for the polyatomic ion.
  • if there are multiples of the polyatomic ion, put the polyatomic ion in parentheses

to complete the table below:

  • you will break into your lab groups.
  • at each station are 4 cards with names on them and numbers. those numbers correspond to the question name on the table below.
  • complete the compound using the cards at the stations. determine the formula and compound name for each.
metal or transition metalnonmetal or polyatomic ionformulacompound name
2. calciumcacl₂calcium chloride
3. copper (ii)
4. lead (iv)
5. nitride
6. borate
7. iodide
8. sulfite

Explanation:

Step1: Recall ion - charge rules

Sodium has a +1 charge ($Na^+$) and chloride has a - 1 charge ($Cl^-$). Using the criss - cross method, the formula is $NaCl$ and the name is sodium chloride.

Step2: Determine calcium - chloride formula

Calcium has a +2 charge ($Ca^{2 + }$) and chloride has a - 1 charge ($Cl^-$). By criss - cross, the formula is $CaCl_2$ and the name is calcium chloride.

Step3: Find copper(II) - chloride formula

Copper(II) has a +2 charge ($Cu^{2+}$) and chloride has a - 1 charge ($Cl^-$). Using criss - cross, the formula is $CuCl_2$ and the name is copper(II) chloride.

Step4: Calculate lead(IV) - chloride formula

Lead(IV) has a +4 charge ($Pb^{4+}$) and chloride has a - 1 charge ($Cl^-$). By criss - cross, the formula is $PbCl_4$ and the name is lead(IV) chloride.

Step5: For nitride

If we consider a metal like sodium (for example, sodium has a +1 charge), nitride ($N^{3 - }$). Using criss - cross, the formula with sodium would be $Na_3N$ and the name is sodium nitride.

Step6: For borate

Let's assume a metal like sodium again. Sodium has a +1 charge and borate ($BO_3^{3 - }$). The formula is $Na_3BO_3$ and the name is sodium borate.

Step7: For iodide

If we take potassium (with a +1 charge) as an example, iodide has a - 1 charge ($I^-$). The formula is $KI$ and the name is potassium iodide.

Step8: For sulfite

If we consider sodium (with a +1 charge), sulfite ($SO_3^{2 - }$). Using criss - cross, the formula is $Na_2SO_3$ and the name is sodium sulfite.

Answer:

Metal or Transition MetalNonmetal or Polyatomic IonFormulaCompound Name
2. CalciumChloride$CaCl_2$Calcium chloride
3. Copper (II)Chloride$CuCl_2$Copper(II) chloride
4. Lead (IV)Chloride$PbCl_4$Lead(IV) chloride
5. Nitride$Na_3N$ (using sodium as an example)Sodium nitride
6. Borate$Na_3BO_3$ (using sodium as an example)Sodium borate
7. Iodide$KI$ (using potassium as an example)Potassium iodide
8. Sulfite$Na_2SO_3$ (using sodium as an example)Sodium sulfite