Question

refer to the accompanying data display that results from a sample of airport data speeds in mbps. complete parts (a) through (c) below
tinterval
(13.046,22.15)
\\( \overline { x } = 17.598 \\)
\\( s x = 16.01712719 \\)
\\( n = 50 \\)
a. express the confidence interval in the format that uses the \less than\ symbol. given that the original listed data use one decimal place, round the confidence interval limits accordingly.
\\( \square \mathrm { mbps } < \mu < \square \mathrm { mbps } \\)
(round to two decimal places as needed.)

Explanation:

Step1: Identify the confidence interval limits

The given confidence interval is \((13.046, 22.15)\)

Step2: Round the limits

Rounding \(13.046\) to two decimal places: \(13.05\)
Rounding \(22.15\) (it is already to two decimal places) remains \(22.15\)

Answer:

\(13.05\) Mbps \(<\mu<22.15\) Mbps