Question

read the passage and use the diagram to answer the next two questions. the figure shows the elements of period 3 and the first 3 elements of group 6a of the periodic table. use the figure to answer questions 10 and 11. which list of symbols, in order from left to right, correctly completes the following passage? from the group 6a elements shown in the diagram, the element with the largest atomic radius is __. in period 3, the element with the largest atomic radius is . the three atoms which would form ions which are smaller in size than their parent atoms are al, mg, and . in period 3, has the highest ionization energy, while in group 6a __ has the highest ionization energy. o, ar, cl, na, se se, na, na, ar, o se, na, cl, ar, se o, ar, na, na, o

Explanation:

• Atomic radius:
• In a group (Group 6A), atomic radius increases down the group. So among \(O\), \(S\), \(Se\), \(Se\) has the largest atomic radius.
• In a period (Period 3), atomic radius decreases from left to right. So \(Na\) has the largest atomic radius in Period 3.
• Ion size:
• Metals (like \(Na\), \(Mg\), \(Al\)) lose electrons to form cations. Cations are smaller than their parent atoms.
• Ionization energy:
• In a period (Period 3), ionization energy generally increases from left to right. \(Ar\) (a noble gas) has a very high ionization energy as it has a stable electron configuration.
• In a group (Group 6A), ionization energy decreases down the group. So \(O\) has the highest ionization energy in Group 6A.

Answer:

Se, Na, Na, Ar, O