Question

the reaction shifts to the right (products). what happens to the amount of no as the reaction shifts?
$2no(g) + o_2(g) \
ightleftharpoons 2no_2(g) + 113.06\\ kj$
the amount of no goes down.
the amount of no goes up.
the amount of no does not change.

Explanation:

In a chemical equilibrium reaction, when the reaction shifts to the right (towards products), the reactants are consumed to form more products. In the given reaction \(2NO(g)+O_2(g)
ightleftharpoons 2NO_2(g)+113.06\space kJ\), NO is a reactant. As the reaction shifts right, NO is used up to produce \(NO_2\), so its amount decreases.

Answer:

The amount of NO goes down.