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Question
quiz - atoms, moles, molecules, mass and volume conversions
there are three mole equalities. they are:
1 mol = 6.02×10²³ particles
1 mol = molar mass in g (periodic table)
1 mol = 22.4 l for a gas at stp
part 1: select best answer for each question (1 point each)
- a single proton has what electrical charge?
a. no charge b. positive charge
c. negative charge d. either a positive or negative charge
- which particles have approximately the same size and mass as each other?
a. neutrons and electrons b. electrons and protons
c. protons and neutrons d. none - all are different in size and mass
- which two particles would be attracted to each other?
a. electrons and neutrons b. electrons and protons
c. protons and neutrons d. all particles are attracted to each other
- the three basic components of an atom are:
a. protons, neutrons, and ions b. protons, neutrons, and electrons
c. protons, neutrinos, and ions d. protium, deuterium, and tritium
- an element is determined by the number of:
a. atoms b. electrons c. neutrons d. protons
- the nucleus of an atom consists of:
a. electrons b. neutrons
c. protons and neutrons d. protons, neutrons, and electrons
part 2: use your periodic table to solve each problem
for each problem calculate the g/mol for each of the following chemicals (1 point each)
- hc₂h₃o₂________________
- c₆h₁₂o₆________________
- c₁₂h₁₉clo________________
Step1: Calculate molar mass of \(HC_2H_3O_2\)
- Molar mass of \(H\) is \(1\space g/mol\), \(C\) is \(12\space g/mol\), \(O\) is \(16\space g/mol\)
- \(HC_2H_3O_2\) has \(4\) \(H\) atoms (\(4\times1\)), \(2\) \(C\) atoms (\(2\times12\)), \(2\) \(O\) atoms (\(2\times16\))
- \(M=(4\times1)+(2\times12)+(2\times16)=4 + 24+32 = 60\space g/mol\)
Step2: Calculate molar mass of \(C_6H_{12}O_6\)
- \(C_6H_{12}O_6\) has \(6\) \(C\) atoms (\(6\times12\)), \(12\) \(H\) atoms (\(12\times1\)), \(6\) \(O\) atoms (\(6\times 16\))
- \(M=(6\times12)+(12\times1)+(6\times16)=72 + 12+96=180\space g/mol\)
Step3: Calculate molar mass of \(C_{12}H_{19}ClO\)
- \(C_{12}H_{19}ClO\) has \(12\) \(C\) atoms (\(12\times12\)), \(19\) \(H\) atoms (\(19\times1\)), \(1\) \(Cl\) atom (\(35.5\)), \(1\) \(O\) atom (\(16\))
- \(M=(12\times12)+(19\times1)+35.5 + 16=144+19 + 35.5+16=214.5\space g/mol\)
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- \(60\space g/mol\)
- \(180\space g/mol\)
- \(214.5\space g/mol\)