questions:
1. balance this reaction:
______ agno₃ + ______ nacl → ______ nano₃ + ______ agcl
2. what type of reaction is this?__________________________

Question

Accepted Answer

# Explanation:
## Step1: Balance the reaction
Count the number of each atom on both sides.
For $Ag$: 1 on left (in $AgNO_3$) and 1 on right (in $AgCl$).
For $N$: 1 on left (in $AgNO_3$) and 1 on right (in $NaNO_3$).
For $O$: 3 on left (in $AgNO_3$) and 3 on right (in $NaNO_3$).
For $Na$: 1 on left (in $NaCl$) and 1 on right (in $NaNO_3$).
For $Cl$: 1 on left (in $NaCl$) and 1 on right (in $AgCl$).
So the balanced equation is $1AgNO_3 + 1NaCl \to 1NaNO_3 + 1AgCl$

## Step2: Identify the reaction type
This is a double - displacement reaction. In a double - displacement reaction, the positive ions ($Ag^+$ and $Na^+$) exchange their negative ion partners ($NO_3^-$ and $Cl^-$).

# Answer:
1. $1AgNO_3 + 1NaCl \to 1NaNO_3 + 1AgCl$
2. Double - displacement reaction

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QUESTION IMAGE

Question

Explanation:

Step1: Balance the reaction

Step2: Identify the reaction type

Answer: