Question

question
what is the osmotic pressure (in atmospheres) of a 0.750 m solution of glucose at 300 k?

• use ( r = 0.08206 \frac{l \text{ atm}}{\text{mol k}} ) for the gas constant.
• your answer should have three significant figures. (round your answer to one decimal place).
• do not include units in your answer.

provide your answer below:

atm

Explanation:

Step1: Recall the osmotic pressure formula

The formula for osmotic pressure ($\pi$) is $\pi = iMRT$. Since glucose is a non - electrolyte, $i = 1$.

Step2: Substitute the given values

Given $M=0.750\space mol/L$, $R = 0.08206\space\frac{L\cdot atm}{mol\cdot K}$, and $T = 300\space K$.
Substitute into the formula: $\pi=(1)\times(0.750)\times(0.08206)\times(300)$.
First, calculate $(0.750)\times(0.08206)=0.061545$.
Then, $0.061545\times300 = 18.4635$.

Answer:

$18.5$