Question

question 1
1 pts
indicate which compounds are soluble in water.
□ nano₃
□ pbso₄
□ li₂co₃
□ fe(oh)₃

Explanation:

Step1: Analyze $\ce{NaNO_{3}}$

Sodium nitrate ($\ce{NaNO_{3}}$) - Compounds containing $\ce{Na+}$ (sodium ion) and $\ce{NO_3^-}$ (nitrate ion) are generally soluble in water. So $\ce{NaNO_{3}}$ is soluble.

Step2: Analyze $\ce{PbSO_{4}}$

Lead(II) sulfate ($\ce{PbSO_{4}}$) - Sulfates are mostly soluble, but $\ce{Pb^{2+}}$ (lead(II) ion) forms an insoluble sulfate. So $\ce{PbSO_{4}}$ is insoluble.

Step3: Analyze $\ce{Li_{2}CO_{3}}$

Lithium carbonate ($\ce{Li_{2}CO_{3}}$) - Carbonates are generally insoluble, but lithium carbonate is an exception and is soluble in water (since $\ce{Li+}$ is a Group 1 metal ion, and Group 1 carbonates are soluble). So $\ce{Li_{2}CO_{3}}$ is soluble.

Step4: Analyze $\ce{Fe(OH)_{3}}$

Iron(III) hydroxide ($\ce{Fe(OH)_{3}}$) - Hydroxides of transition metals (like $\ce{Fe^{3+}}$) are generally insoluble in water. So $\ce{Fe(OH)_{3}}$ is insoluble.

Answer:

The soluble compounds are $\ce{NaNO_{3}}$ and $\ce{Li_{2}CO_{3}}$. So the correct checkboxes are for $\ce{NaNO_{3}}$ and $\ce{Li_{2}CO_{3}}$.