Question

question 1
1 pts
determine the mass of solute present in 537 g of aqueous solution that is 3.47% srcl₂ by mass?
15500g srcl₂
3.47g srcl₂
18.6g srcl₂
1.55g srcl₂

Explanation:

Step1: Recall mass percent formula

Mass percent of solute = $\frac{\text{mass of solute}}{\text{mass of solution}} \times 100\%$. Rearranged, mass of solute = (mass percent / 100%) × mass of solution.

Step2: Plug in values

Mass percent = 3.47%, mass of solution = 537 g. So mass of solute = $\frac{3.47}{100} \times 537$.

Step3: Calculate

$\frac{3.47}{100} \times 537 = 0.0347 \times 537 \approx 18.6$ g.

Answer:

18.6g SrCl₂ (the third option: 18.6g SrCl₂)