Question

question 2 (0.5 points) ✓ saved listen the correct names of pbcl₄ and nibr₂ are: 1) iron(iv) chloride and nitrogen bromide 2) lead(iv)chloride and nickel(ii)bromide 3) lead chloride (iv) and nitrogen bromide 4) iron chloride and nickel bromide (ii)

Explanation:

For \(PbCl_4\), \(Pb\) is the chemical symbol for lead. Chloride is \(Cl^-\). Using the Roman - numeral system for naming ionic compounds with multivalent metals, in \(PbCl_4\), since \(Cl^-\) has a charge of \(- 1\) and there are 4 \(Cl^-\) ions, the charge on \(Pb\) is \(+4\). So it is lead(IV) chloride.

For \(NiBr_2\), \(Ni\) is the chemical symbol for nickel. Bromide is \(Br^-\). Since \(Br^-\) has a charge of \(-1\) and there are 2 \(Br^-\) ions, the charge on \(Ni\) is \(+2\). So it is nickel(II) bromide.

Answer:

1. Lead(IV)chloride and Nickel(II)Bromide