Question

question 3 (2 points) ✓ saved
how many grams of nacl are there in 2.00 l of a 2.00 m solution? the molar mass of nacl is 58.44 g/mol.
first we get the moles
1 mol
(2 l)(-------------) = 3 mol
4 l
then we convert into grams
5 g
(6 mol)(----------) = 7 g
8 mol
a. 0 b. 1 c. 2 d. 3 e. 4 f. 5
g. 6 h. 234 i. 58.44 j. 100. k 1.71
l 0.856 m. 10.0

Explanation:

Step1: Calculate the number of moles

The formula for molarity \(M=\frac{n}{V}\), where \(M\) is molarity, \(n\) is the number of moles, and \(V\) is the volume in liters. Rearranging for \(n\), we get \(n = M\times V\).
Given \(M = 2.00\space M\) and \(V=2.00\space L\), so \(n=(2.00\space mol/L)\times(2.00\space L) = 4.00\space mol\)

Step2: Convert moles to grams

The formula for mass \(m=n\times M_m\), where \(n\) is the number of moles and \(M_m\) is the molar mass.
Given \(n = 4.00\space mol\) and \(M_m=58.44\space g/mol\), so \(m=(4.00\space mol)\times(58.44\space g/mol)=233.76\approx234\space g\)

Now, filling in the blanks:

1. \(4\) (from \(n = M\times V=2\times2\))
2. \(2\) (volume \(V = 2.00\space L\))
3. \(4\) (result of \(2\times2\))
4. \(1\) (unit conversion factor for molarity \(mol/L\), denominator \(L\))
5. \(58.44\) (molar mass of \(NaCl\))
6. \(4\) (number of moles)
7. \(234\) (result of \(4\times58.44\))
8. \(1\) (unit conversion factor for molar - mass \(g/mol\), denominator \(mol\))

Answer:

1. \(E\)
2. \(C\)
3. \(E\)
4. \(B\)
5. \(I\)
6. \(E\)
7. \(H\)
8. \(B\)