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Question
question 1 points 1
the normality of 1 m hcl is _.
4n
0.5n
2n
1n
Step1: Recall the formula for normality
Normality ($N$) = Molarity ($M$) × n - factor.
For $HCl$, the n - factor is the number of $H^{+}$ ions it can donate. $HCl$ donates 1 $H^{+}$ ion, so n - factor = 1.
Step2: Calculate the normality
Given $M = 1\ M$.
Using the formula $N = M\times n - factor$.
Substitute $M = 1$ and $n - factor=1$ into the formula: $N=1\times1$.
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1N