Question

question 1 (2 points)
how many moles in 3.0 l of a 2.00 m solution of sodium chloride?
the conversion factor is always the concentration, in this case _1_
to calculate the moles we can cancel out liters
_2_ mol
(_3_l)(_4_)=_4_mol
1l
a. 0.00
b. 1.00
c. 2.00
d. 3.00
e. 2.00 mol/l
f. 4.00
g. 5.00
h. 6.00
i. 58.44 g/mol
j. 58.44
k. 351
l. 10.00
m. 584.4

Explanation:

Step1: Recall the formula for moles

The formula for moles \(n\) in a solution is \(n = C\times V\), where \(C\) is the concentration (in \(mol/L\)) and \(V\) is the volume (in \(L\)).

Step2: Substitute the given values

Given \(C = 2.00\ mol/L\) and \(V=3.0\ L\).
Substitute into the formula: \(n=(2.00\ mol/L)\times(3.0\ L)\)

Step3: Calculate the result

\(n = 6.00\ mol\)

Answer:

C. 6.00