Question

question 4 (2 points)
how many l of a 2.00 m nacl solution are need to have 100. g of nacl? the molar mass of nacl is 58.44 g/mol.
first we get the moles
1 mol
(2 g)(----------) = 3 mol
4 g
then we convert into liters
5 l
(6 mol)(----------) = 7 l
8 mol
a. 0 b. 1 c. 2 d. 3 e. 4 f. 5
g. 6 h. 234 i. 58.44 j. 100. k. 1.71
l. 0.856 m. 10.0

Explanation:

Step1: Calculate moles of NaCl

Moles \(n=\frac{m}{M}\), where \(m = 100. g\) (mass of \(NaCl\)) and \(M=58.44g/mol\) (molar mass of \(NaCl\)).
\(n=\frac{100. g}{58.44g/mol}\approx1.71mol\)

Step2: Calculate volume of solution

Molarity \(M = \frac{n}{V}\), so \(V=\frac{n}{M}\). Given \(M = 2.00M\) and \(n\approx1.71mol\)
\(V=\frac{1.71mol}{2.00mol/L}=0.856L\)

Answer:

1. \(K\) (for \(1.71\) in moles calculation)
2. \(J\) (for \(100. g\) in mass value)
3. \(K\) (result of moles calculation)
4. \(I\) (for \(58.44g\) in molar - mass value)
5. \(L\) (for \(0.856L\) in volume result)
6. \(K\) (moles value \(1.71\) for volume conversion)
7. \(L\) (final volume \(0.856L\))
8. \(C\) (for \(2.00mol\) in molarity value)