QUESTION IMAGE
Question
question 9 (3 points)
fill in all of the missing information; 1 symbol and 3 numbers (from the letter choices below)
200 a 200 c
po + e → bi + d
84 b 83 0
a = 1
b = 2
c = 3
d = 4
a. -1 b. 0 c. 1 d. 2 e. 3 f. 4 g. e
h. gamma i. alpha j. fr k. ra l. ac m. cs
n. ba o. 87 p. 88 q. 222 r. 218
s. 226 t. proton
Step1: Balance mass - number
In a nuclear reaction, the sum of mass - numbers on the left - hand side equals the sum of mass - numbers on the right - hand side. The mass - number of Po is 200 and for e (electron) is 0. So, $200+0 = 200 + C$. Thus, $C = 0$.
Step2: Balance atomic number
The atomic number of Po is 84 and for e is - 1. The atomic number of Bi is 83. So, $84+( - 1)=83 + 0$. The symbol for an electron is $e$ and its charge (atomic number) is - 1, so $A=-1$.
Step3: Determine the particle D
Since the mass - number and atomic number on both sides of the equation are already balanced with the given particles and values, and we know that in electron capture (which is what this reaction represents), a neutrino is also emitted. But among the given choices, for the balance of the reaction in terms of the information provided, the particle D is an electron $e$ (as we have already accounted for the mass - number and atomic number changes). And the value of B (atomic number of the electron) is - 1.
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A. -1
B. -1
C. 0
D. G. e