Question

question 8 (1 point) ✓ saved
given the following reaction mechanism, what is the equation for the overall reaction?
2a --> b + 2c (slow)
b + c --> d + e (fast)
c + d --> e + f (fast)
2a-->2e + f
2a + b + 2c --> d + 2e + f
2a + 2c --> 2e + f
2a + b + 2c + d --> b + 2c + d + 2e + f
2a + c --> 2e + f

Explanation:

Step1: Add all the reactions

$$\begin{align*} 2A&\to B + 2C\\ B + C&\to D + E\\ C + D&\to E + F\\ \end{align*}$$

Adding them gives: \(2A + B + C+ C + D\to B + 2C+ D + 2E + F\)

Step2: Cancel out common terms

Cancel \(B\), \(C\), and \(D\) from both sides.

Answer:

\(2A\to 2E + F\) (First option)