Question

question 1 (1 point)
name the ion
po^{-2}

question 2 (1 point)
name the ion
pb^{+2}

Explanation:

Question 1

Step1: Identify the element

The symbol \(Po\) represents the element Polonium.

Step2: Determine the ion name

Since it has a charge of \(- 2\), it is an anion. The naming of anions for non - transition metals (in this case, Polonium is a metalloid but follows similar naming rules for simple ions) is done by changing the ending of the element name to “-ide”. So, \(Po^{-2}\) is called Polonide ion.

Question 2

Step1: Identify the element

The symbol \(Pb\) represents the element Lead.

Step2: Determine the ion name

Since it has a charge of \(+2\), for metals that can have multiple charges (Lead can have \(+2\) and \(+4\) charges), we use the Stock system. The Stock system uses Roman numerals in parentheses to denote the charge. So, \(Pb^{+2}\) is called Lead(II) ion.

Answer:

1. Polonide ion
2. Lead(II) ion