Question

question 5 (1 point) listen the balanced molecular equation for the reaction of aqueous nitric acid and aqueous potassium hydroxide is: 1) hn(aq) + kh(aq) → khn(aq) 2) 2hno₂(aq) + 2k(oh)₂(aq) → 2kn(aq) + 3h₂o(l) 3) hno₃(aq) + koh(aq) → kno₃ (aq) + k₂o(aq) 4) hno₃(aq) + koh(aq) → kno₃(aq) + h₂o(l)

Explanation:

Step1: Identify Reactants

Nitric acid is $\ce{HNO3}$ (aq), potassium hydroxide is $\ce{KOH}$ (aq). They are an acid and a base, so they undergo a neutralization reaction.

Step2: Recall Neutralization Reaction

In neutralization, acid + base → salt + water. The salt from $\ce{HNO3}$ and $\ce{KOH}$ should be $\ce{KNO3}$, and water is $\ce{H2O(l)}$.

Step3: Check Each Option

• Option 1: Formulas are incorrect (HN, KH, KHN are not valid for these compounds).
• Option 2: Reactants are incorrect ($\ce{HNO2}$ is nitrous acid, $\ce{K(OH)2}$ is wrong; K has +1 charge, so $\ce{KOH}$ is correct, not $\ce{K(OH)2}$).
• Option 3: Products are wrong; should form $\ce{H2O}$, not $\ce{K2O}$.
• Option 4: $\ce{HNO3(aq) + KOH(aq) -> KNO3(aq) + H2O(l)}$ matches neutralization: acid + base → salt ($\ce{KNO3}$) + water ($\ce{H2O}$), and atoms are balanced (H:1+1=2, O:3+1=4; K:1, N:1 on left; K:1, N:1, O:3+1=4, H:2 on right).

Answer:

1. $\ce{HNO3(aq) + KOH(aq) -> KNO3(aq) + H2O(l)}$