Question

question 2 (1 point)
how many regions of electron density does the nitrogen have in this compound?
a) 4
b) 3
c) 1
d) 2

Explanation:

Step1: Identify bonding pairs and lone pairs

In the \(NH_3\) (ammonia) molecule, nitrogen (\(N\)) forms three single bonds with hydrogen (\(H\)) atoms (bonding pairs). There is also one lone pair of electrons on the nitrogen atom.

Step2: Calculate electron - density regions

The formula for the number of electron - density regions is \( \text{Number of bonding pairs}+\text{Number of lone pairs}\). Here, the number of bonding pairs \(= 3\) (from \(N - H\) bonds) and the number of lone pairs \(= 1\). So, the number of electron - density regions \(=3 + 1=4\).

Answer:

A. 4