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Question
question 1 (1 point)
balance the equation using numbers 1 to infinity.
____ c₃h₈ + __ o₂ → __ co₂ + ____ h₂o
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Step1: Balance Carbon
In \( \ce{C3H8} \), there are 3 C atoms. So, \( \ce{CO2} \) should have a coefficient of 3 to balance C: \( \boldsymbol{1}\ce{C3H8} + \ce{O2}
ightarrow \boldsymbol{3}\ce{CO2} + \ce{H2O} \)
Step2: Balance Hydrogen
In \( \ce{C3H8} \), there are 8 H atoms. Each \( \ce{H2O} \) has 2 H, so \( \ce{H2O} \) coefficient: \( \frac{8}{2} = 4 \): \( \ce{C3H8} + \ce{O2}
ightarrow 3\ce{CO2} + \boldsymbol{4}\ce{H2O} \)
Step3: Balance Oxygen
On right: \( 3\times2 + 4\times1 = 10 \) O atoms. Each \( \ce{O2} \) has 2 O, so \( \ce{O2} \) coefficient: \( \frac{10}{2} = 5 \): \( \boldsymbol{1}\ce{C3H8} + \boldsymbol{5}\ce{O2}
ightarrow \boldsymbol{3}\ce{CO2} + \boldsymbol{4}\ce{H2O} \)
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