Question

question
express in simplest radical form.
\sqrt{63}
answer attempt 2 out of 5
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Explanation:

Step1: Factor the radicand

Factor 63 into prime factors: \( 63 = 9\times7 \), where 9 is a perfect square.

Step2: Apply square root property

Using the property \( \sqrt{ab}=\sqrt{a}\times\sqrt{b} \) (for \( a\geq0, b\geq0 \)), we have \( \sqrt{63}=\sqrt{9\times7}=\sqrt{9}\times\sqrt{7} \).

Step3: Simplify the perfect square root

Since \( \sqrt{9} = 3 \), substitute it back: \( \sqrt{9}\times\sqrt{7}=3\sqrt{7} \).

Answer:

\( 3\sqrt{7} \)