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Question
question
express in simplest radical form.
\\(\sqrt{2}\sqrt{20}\\)
Step1: Use the property of radicals $\sqrt{a}\sqrt{b}=\sqrt{ab}$
$\sqrt{2}\sqrt{20}=\sqrt{2\times20}$
Step2: Calculate the product inside the radical
$2\times20 = 40$, so we have $\sqrt{40}$
Step3: Simplify $\sqrt{40}$ by factoring out the perfect square
$40 = 4\times10$, so $\sqrt{40}=\sqrt{4\times10}$
Step4: Use the property $\sqrt{ab}=\sqrt{a}\sqrt{b}$ again
$\sqrt{4\times10}=\sqrt{4}\sqrt{10}$
Step5: Simplify $\sqrt{4}$
$\sqrt{4}=2$, so we get $2\sqrt{10}$
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$2\sqrt{10}$