Question

question 1
a bond order of 1.5 represents a stable chemical bond.
true
false
question 2
what is the hybridization on the central atom of xebr₂?
sp
sp³d
sp²
sp²d²
sp³

Explanation:

Question 1

Bond order is a measure of the stability of a chemical bond. A bond order of 1.5 indicates a stable bond. For example, in some resonance - stabilized molecules, non - integer bond orders like 1.5 can be found and these bonds are stable.

For \(XeBr_{2}\), first, find the number of electron - pair domains around the central \(Xe\) atom. The formula for the number of electron - pair domains \(n=\frac{V + M - C+A}{2}\), where \(V\) is the valence electrons of the central atom (\(Xe\) has 8 valence electrons), \(M\) is the number of monovalent atoms (\(Br\) is monovalent, and there are 2 \(Br\) atoms), \(C\) is the charge of the cation (0 in this case), and \(A\) is the charge of the anion (0 in this case). So \(n=\frac{8 + 2-0 + 0}{2}=5\). The hybridization corresponding to 5 electron - pair domains is \(sp^{3}d\).

Answer:

True

Question 2