Question

question 51 (2 points)
how many electrons are there in the highest occupied energy level of atoms in group 5a elements?
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question 52 (2 points)
how many electrons are present in the d sublevel of a neutral atom of nickel?
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question 53 (2 points)
how many electrons are in a rubidium ion (rb)?
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question 54 (2 points)
how many electrons does the ion ca contain?
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Explanation:

Question 51

Step1: Determine the electron configuration rule for group elements

In the periodic table, the number of electrons in the highest - occupied energy level (valence electrons) for group \(nA\) elements is \(n\). For Group \(5A\) elements, \(n = 5\).

Question 52

Step1: Write the electron configuration of nickel

The atomic number of nickel (\(Ni\)) is \(28\). The electron configuration of \(Ni\) is \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{8}\). The \(d\) sub - level in nickel (\(3d\)) has \(8\) electrons.

Question 53

Step1: Find the atomic number of rubidium

The atomic number of rubidium (\(Rb\)) is \(37\). A \(Rb^{+}\) ion has lost one electron. So the number of electrons in \(Rb^{+}\) is \(37-1=36\).

Question 54

Step1: Find the atomic number of calcium

The atomic number of calcium (\(Ca\)) is \(20\). A \(Ca^{2 +}\) ion has lost two electrons. So the number of electrons in \(Ca^{2+}\) is \(20 - 2=18\).

Answer:

Question 51: \(5\)
Question 5[SSE Completed, Client Connection Error][SSE Completed, Client Connection Error][LLM SSE On Failure]