Question

question 1
8.33 pts
br₂ (l) + nal (aq) → nabr (aq) + i₂ (s)
total ionic equation: →
spectator ions:
net ionic equation: →

Explanation:

Step1: Write the total ionic equation

Break the aqueous ionic compounds into ions.
$$\text{Br}_{2}(l)+2\text{Na}^{+}(aq)+2\text{I}^{-}(aq)\to 2\text{Na}^{+}(aq)+2\text{Br}^{-}(aq)+\text{I}_{2}(s)$$

Step2: Identify spectator ions

Spectator ions are ions that appear on both sides of the equation. Here, $\text{Na}^{+}$ is the spectator ion.

Step3: Write the net ionic equation

Cancel out the spectator ions from the total ionic equation.
$$\text{Br}_{2}(l)+2\text{I}^{-}(aq)\to 2\text{Br}^{-}(aq)+\text{I}_{2}(s)$$

Answer:

• total ionic equation: $\text{Br}_{2}(l)+2\text{Na}^{+}(aq)+2\text{I}^{-}(aq)\to 2\text{Na}^{+}(aq)+2\text{Br}^{-}(aq)+\text{I}_{2}(s)$
• spectator ions: $\text{Na}^{+}$
• net ionic equation: $\text{Br}_{2}(l)+2\text{I}^{-}(aq)\to 2\text{Br}^{-}(aq)+\text{I}_{2}(s)$