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Question
question 18 (1 point)
what is the ph of a 0.0001 m aqueous solution of hcl?
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Step1: Determine the concentration of \(H^+\) ions
Since \(HCl\) is a strong acid, it completely dissociates in water. The chemical equation for the dissociation of \(HCl\) is \(HCl
ightarrow H^++Cl^-\). So, if the concentration of \(HCl\) is \(C = 0.0001\space M=1\times10^{- 4}\space M\), then the concentration of \(H^+\) ions, \([H^+]=1\times 10^{-4}\space M\)
Step2: Calculate the \(pH\) value
The formula for \(pH\) is \(pH=-\log[H^+]\). Substitute \([H^+]=1\times 10^{-4}\) into the formula:
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