Question

question 14 (1 point)
two isomers of c4o2h8 are:
ch3ch2c-o-ch3 and h-c-o-ch2ch2ch3
the names of both these compounds are
a) methyl propanoate and propyl methanoate
b) propyl methanoate and methyl methanoate
c) propyl propanoate and methyl propanoate
d) propyl methanoate and methyl propanoate
e) none of the above

Explanation:

For the first compound \(CH_3CH_2C - O - CH_3\), the ester is named by first naming the alkyl group (\(CH_3 -\) is methyl) attached to the oxygen and then the acyl part (\(CH_3CH_2CO -\) is propanoate). So it is methyl propanoate.
For the second compound \(H - C - O - CH_2CH_2CH_3\), the alkyl group attached to the oxygen is \(CH_3CH_2CH_2 -\) (propyl) and the acyl part is \(HCO -\) (methanoate). So it is propyl methanoate.

Answer:

A. methyl propanoate and propyl methanoate