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question 14
in a beaker of volume 15.45 l there are 6.25 moles of a gas. if the number of moles is reduced to 1.26 moles what will be the new volume?
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l
Step1: Apply Avogadro's Law
Avogadro's Law is \( \frac{V_1}{n_1}=\frac{V_2}{n_2} \), where \( V_1 = 15.45\ L \), \( n_1=6.25\ mol \), \( n_2 = 1.26\ mol \).
Step2: Solve for \( V_2 \)
Rearrange the formula to \( V_2=\frac{V_1\times n_2}{n_1} \). Substitute the values: \( V_2=\frac{15.45\times1.26}{6.25} \).
First, calculate \( 15.45\times1.26 = 19.467 \). Then, \( V_2=\frac{19.467}{6.25}=3.11472\ L \).
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\( 3.11\ L \) (rounded to two decimal places)