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Question
question 13 (1 poi
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the correct names of pbcl₄ and nibr₂ are:
- iron(iv) chloride and nitrogen bromide
- lead(iv)chloride and nickel(ii)bromide
- lead chloride (iv) and nitrogen bromide
- lead(ii)chloride and nickel(i)bromide
Step1: Analyze \( \text{PbCl}_4 \)
- \( \text{Pb} \) is lead. Chloride (\( \text{Cl}^- \)) has a charge of -1, and there are 4 \( \text{Cl}^- \), so total negative charge is \( 4\times(-1) = -4 \). To balance, \( \text{Pb} \) must have a +4 charge. So the name is lead(IV) chloride.
Step2: Analyze \( \text{NiBr}_2 \)
- \( \text{Ni} \) is nickel. Bromide (\( \text{Br}^- \)) has a charge of -1, and there are 2 \( \text{Br}^- \), so total negative charge is \( 2\times(-1) = -2 \). To balance, \( \text{Ni} \) must have a +2 charge. So the name is nickel(II) bromide.
Step3: Evaluate options
- Option 1: Incorrect (uses iron and nitrogen, not lead and nickel).
- Option 2: Matches the names we derived (lead(IV) chloride and nickel(II) bromide).
- Option 3: Incorrect (wrong naming format and uses nitrogen).
- Option 4: Incorrect (charges for lead and nickel are wrong).
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- Lead(IV)chloride and Nickel(II)Bromide