Question

question 10
1 pts
match each orbital in the list below with the correct description for a comparison between 1s,
2p, 3s, 4d. choose only one is correct.
4d has five degenerate orbitals.
1s has the highest energy of the group.
2p has two degenerate orbitals.
3s has the lowest energy of the group.

Explanation:

• For 4d: The angular momentum quantum number \( l = 2 \) for d - orbitals. The number of degenerate orbitals for a given \( l \) is \( 2l + 1 \). For \( l=2 \), \( 2\times2 + 1=5 \).
• For 1s: Energy of orbitals increases with the principal quantum number \( n \) and the value of \( l \). Among 1s (\( n = 1,l = 0 \)), 2p (\( n=2,l = 1 \)), 3s (\( n = 3,l=0 \)), 4d (\( n = 4,l = 2 \)), 1s has the lowest energy.
• For 2p: For p - orbitals (\( l = 1 \)), the number of degenerate orbitals is \( 2l+1=3 \) (not 2).
• For 3s: 1s has a lower energy than 3s as \( n = 1<3 \).

Answer:

4d has five degenerate orbitals.