Question

question 6 of 10
points possible: 1.00
a student mixes 5.0 ml of 3.0% h₂o₂, 8.1 ml of 0.50 m ki, and 50.0 ml of distilled water. what is the final concentration of ki in the reaction mixture, in m?
type answer:
enter a number

Explanation:

Step1: Calculate the total volume of the solution

The total volume \(V_{total}\) is the sum of the volumes of \(H_2O_2\), \(KI\), and distilled water.
\(V_{total}=5.0\space mL + 8.1\space mL+50.0\space mL = 63.1\space mL\)

Step2: Use the dilution formula \(C_1V_1 = C_2V_2\)

We know that \(C_1 = 0.50\space M\), \(V_1=8.1\space mL\), and \(V_2 = 63.1\space mL\). We want to find \(C_2\).
From \(C_2=\frac{C_1V_1}{V_2}\), substituting the values:
\(C_2=\frac{0.50\space M\times8.1\space mL}{63.1\space mL}\)
\(C_2=\frac{4.05}{63.1}\space M\approx0.064\space M\)

Answer:

\(0.064\)