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Question
question 10 (5 points)
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2nh₃→n₂ + 3h₂
if 2.22 moles of ammonia (nh₃) decomposes according to the reaction shown, how many moles of hydrogen (h₂) are formed?
a) 2.22 moles of h₂
b) 3.33 moles of h₂
c) 1.11 moles of h₂
d) 6.66 moles of h₂
Step1: Determine mole ratio
From the reaction $2\ce{NH3}
ightarrow \ce{N2} + 3\ce{H2}$, the mole ratio of $\ce{NH3}$ to $\ce{H2}$ is $2:3$.
Step2: Set up proportion
Let $x$ be moles of $\ce{H2}$. Then $\frac{2}{3} = \frac{2.22}{x}$.
Step3: Solve for $x$
Cross - multiply: $2x = 3\times2.22$. So $x=\frac{3\times2.22}{2}= 3.33$.
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B) 3.33 moles of $\ce{H2}$