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what is the formula for the ionic compound containing ions of barium and sulfur?
a) ba₂s₃
b) bas₂
c) ba₂s
d) ba₂s₂
e) bas
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Step1: Determine the charges of ions
Barium (\(Ba\)) is in group 2 of the periodic table, so it forms \(Ba^{2+}\) ion. Sulfur (\(S\)) is in group 16, so it forms \(S^{2 -}\) ion.
Step2: Balance the charges
For an ionic compound, the sum of the charges of cations and anions should be zero. Let the formula be \(Ba_xS_y\). Then \(2x+( - 2)y = 0\). If \(x = 1\) and \(y = 1\), \(2\times1+( - 2)\times1=2 - 2=0\)
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E. BaS