Question

question 10 (1 po listen how many mols are present in 0.02698 g of aluminum (al = 26.98amu)? 1) 0.02698millimol 2) 26.98mol 3) 1.000 millimol 4) 1.000mol

Explanation:

Step1: Recall the formula for moles

The formula to calculate moles ($n$) is $n = \frac{\text{mass (in grams)}}{\text{molar mass (in g/mol)}}$. The molar mass of Al is 26.98 g/mol (since 1 amu is approximately 1 g/mol for molar mass).

Step2: Substitute the values

Given mass = 0.02698 g, molar mass = 26.98 g/mol. So $n = \frac{0.02698\ \text{g}}{26.98\ \text{g/mol}} = 0.001\ \text{mol}$.

Step3: Convert moles to millimoles

Since 1 mol = 1000 millimol, $0.001\ \text{mol} \times 1000 = 1.000\ \text{millimol}$.

Answer:

1. 1.000 millimol