Question

if the n quantum number of an atomic orbital is 1, what are the possible values of /? select all that apply. penalties are applied for incorrect guesses. select one or more: -3 -2 -1 0 1 2 3

Explanation:

In quantum mechanics, for a given principal quantum number \(n\), the angular momentum quantum number \(l\) can take values from \(0\) to \(n - 1\). Here, \(n = 1\), so \(l=0\). Negative values of \(l\) are not allowed as \(l\) represents the magnitude of the angular momentum and is a non - negative integer. Values of \(l\) greater than \(n - 1\) (in this case, greater than \(0\)) are also not allowed for the given \(n\).

Answer:

\(0\) (i.e., the option with value \(0\))