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Question
#_______ previous answer: 0.4
determine a linear model for the following data:
Step1: Calculate the mean of \(x\) and \(y\)
$$
\bar{x}=\frac{6 + 27+14 + 38+63+32}{6}=\frac{180}{6}=30
$$
$$
\bar{y}=\frac{76 + 43+70 + 34+17+46}{6}=\frac{286}{6}\approx47.67
$$
Step2: Calculate the numerator and denominator for slope \(m\)
$$
\text{Numerator}=\sum_{i = 1}^{6}(x_{i}-\bar{x})(y_{i}-\bar{y})=(6 - 30)(76 - 47.67)+(27 - 30)(43 - 47.67)+(14 - 30)(70 - 47.67)+(38 - 30)(34 - 47.67)+(63 - 30)(17 - 47.67)+(32 - 30)(46 - 47.67)
$$
$$
=-24\times28.33-3\times(-4.67)-16\times22.33 + 8\times(-13.67)+33\times(-30.67)+2\times(-1.67)
$$
$$
=-680 - (-14) - 357.28-109.36-1012.11 - 3.34=-2148.09
$$
$$
\text{Denominator}=\sum_{i = 1}^{6}(x_{i}-\bar{x})^{2}=(6 - 30)^{2}+(27 - 30)^{2}+(14 - 30)^{2}+(38 - 30)^{2}+(63 - 30)^{2}+(32 - 30)^{2}
$$
$$
=(-24)^{2}+(-3)^{2}+(-16)^{2}+8^{2}+33^{2}+2^{2}=576 + 9+256+64+1089+4 = 1998
$$
$$
m=\frac{-2148.09}{1998}\approx - 1.08
$$
Step3: Calculate the intercept \(b\)
$$
b=\bar{y}-m\bar{x}=47.67-(-1.08)\times30=47.67 + 32.4=80.07
$$
Step4: Write the linear model
The linear model is \(y=-1.08x + 80.07\)
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\(y=-1.08x + 80.07\)