Question

pre - ap chemistry bellwork 10/27
▶organize your binder.
▶answer this question on your bellwork sheet:
▶how many electrons can the 3s sublevel hold?
▶write the electron configuration for na.

Explanation:

Step1: Determine the number of electrons in 3s sublevel

The formula for the number of electrons in a sublevel is \(2(2l + 1)\), where \(l = 0\) for s - sublevel.
Substituting \(l = 0\) into the formula: \(2(2\times0 + 1)=2\).

Step2: Write the electron configuration for Na

Sodium (Na) has an atomic number of 11.
Using the Aufbau principle, electrons fill orbitals in order of increasing energy.
The electron configuration is \(1s^{2}2s^{2}2p^{6}3s^{1}\).

Answer:

The 3s sublevel can hold 2 electrons. The electron configuration of Na is \(1s^{2}2s^{2}2p^{6}3s^{1}\).