practice problems!
now you try balancing some chemical equations for yourself!
1. ____ k + ____ h₂o → ____ koh + ____ h₂
2. ____ al + ____ hcl → ____ alcl₃ + ____ h
3. ____ agno₃ + ____ ni → ____ ni(no₃)₂ + ____ ag
4. ____ h₃po₄ + ____ koh → ____ k₃po₄ + ____ h₂o

Question

Accepted Answer

# Explanation:
## Step1: Balance hydrogen and oxygen in the first equation
For the equation $K + H_{2}O
ightarrow KOH + H_{2}$, we first look at the hydrogen atoms. There are 2 hydrogen atoms in $H_{2}O$ and 3 hydrogen atoms on the right - hand side ($1$ in $KOH$ and $2$ in $H_{2}$). If we put a coefficient of $2$ in front of $H_{2}O$, we have $2H_{2}O$ (4 hydrogen atoms). Then, if we put a coefficient of $2$ in front of $KOH$ (2 hydrogen atoms from $KOH$) and a coefficient of $1$ in front of $H_{2}$, the hydrogen atoms are balanced. Now for potassium atoms, if we put a coefficient of $2$ in front of $K$, the equation $2K + 2H_{2}O=2KOH + H_{2}$ is balanced.
## Step2: Balance chlorine and hydrogen in the second equation
For the equation $Al+HCl
ightarrow AlCl_{3}+H_{2}$, we first balance the chlorine atoms. Since there are 3 chlorine atoms in $AlCl_{3}$, we put a coefficient of $3$ in front of $HCl$. Now for hydrogen atoms, we have 3 hydrogen atoms from $HCl$. To balance the hydrogen atoms (since we want $H_{2}$), we multiply $HCl$ by $6$ (so we have 6 hydrogen atoms). Then, to balance aluminium, we put a coefficient of $2$ in front of $Al$. The balanced equation is $2Al + 6HCl=2AlCl_{3}+3H_{2}$
## Step3: Balance nitrate and metal atoms in the third equation
For the equation $AgNO_{3}+Ni
ightarrow Ni(NO_{3})_{2}+Ag$, we first balance the nitrate ions. Since there are 2 nitrate ions in $Ni(NO_{3})_{2}$, we put a coefficient of $2$ in front of $AgNO_{3}$. Then, to balance the silver atoms, we put a coefficient of $2$ in front of $Ag$. The balanced equation is $2AgNO_{3}+Ni = Ni(NO_{3})_{2}+2Ag$
## Step4: Balance potassium and hydrogen in the fourth equation
For the equation $H_{3}PO_{4}+KOH
ightarrow K_{3}PO_{4}+H_{2}O$, we first balance the potassium atoms. Since there are 3 potassium atoms in $K_{3}PO_{4}$, we put a coefficient of $3$ in front of $KOH$. Now for hydrogen atoms, we have $3$ hydrogen atoms from $H_{3}PO_{4}$ and $3$ hydrogen atoms from $KOH$ (total $6$ hydrogen atoms on the left). On the right - hand side, in $H_{2}O$, if we put a coefficient of $3$ in front of $H_{2}O$ (6 hydrogen atoms), the equation $H_{3}PO_{4}+3KOH = K_{3}PO_{4}+3H_{2}O$ is balanced

# Answer:
1. $2K + 2H_{2}O=2KOH + H_{2}$
2. $2Al + 6HCl=2AlCl_{3}+3H_{2}$
3. $2AgNO_{3}+Ni = Ni(NO_{3})_{2}+2Ag$
4. $H_{3}PO_{4}+3KOH = K_{3}PO_{4}+3H_{2}O$

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

Step1: Balance hydrogen and oxygen in the first equation

Step2: Balance chlorine and hydrogen in the second equation

Step3: Balance nitrate and metal atoms in the third equation

Step4: Balance potassium and hydrogen in the fourth equation

Answer: