QUESTION IMAGE
Question
practice
molecule lewis
structure does it
contain polar
bonds? is the
molecule
polar? intermolecular forces present
van der
waals (√)
dipole-dipole
(√)
hydrogen
bonds (√)
pcl₃
f₂
bf₃
ccl₄
hf
h₂o
ch₃cl
Brief Explanations
- For \(PCl_{3}\):
- Lewis structure: Phosphorus is the central atom. It has 5 valence electrons. Three are used to form bonds with chlorine atoms (each chlorine has 7 valence electrons). There is one lone pair on phosphorus. The structure is trigonal pyramidal.
- Polar bonds: \(P - Cl\) bonds are polar (electronegativity difference: \(Cl(3.0) - P(2.1)=0.9\)).
- Molecular polarity: The molecule is polar due to the trigonal - pyramidal shape (lone pair causes asymmetry).
- Intermolecular forces: Van der Waals (all molecules have this), dipole - dipole (because it is polar).
- For \(F_{2}\):
- Lewis structure: Each fluorine atom has 7 valence electrons. They share one pair of electrons (\(F - F\) single bond).
- Polar bonds: \(F - F\) bond is non - polar (electronegativity difference \(=0\)).
- Molecular polarity: Non - polar.
- Intermolecular forces: Only van der Waals.
- For \(BF_{3}\):
- Lewis structure: Boron is the central atom with 3 valence electrons. It forms three \(B - F\) bonds (each \(F\) has 7 valence electrons). The structure is trigonal planar.
- Polar bonds: \(B - F\) bonds are polar (\(F(4.0)-B(2.0)=2.0\)).
- Molecular polarity: Non - polar (trigonal planar symmetry cancels out bond dipoles).
- Intermolecular forces: Only van der Waals.
- For \(CCl_{4}\):
- Lewis structure: Carbon is the central atom with 4 valence electrons. It forms four \(C - Cl\) bonds (each \(Cl\) has 7 valence electrons). The structure is tetrahedral.
- Polar bonds: \(C - Cl\) bonds are polar (\(Cl(3.0)-C(2.5)=0.5\)).
- Molecular polarity: Non - polar (tetrahedral symmetry cancels out bond dipoles).
- Intermolecular forces: Only van der Waals.
- For \(HF\):
- Lewis structure: Hydrogen (1 valence electron) and fluorine (7 valence electrons) share one pair (\(H - F\) bond).
- Polar bonds: \(H - F\) bond is polar (\(F(4.0)-H(2.1)=1.9\)).
- Molecular polarity: Polar.
- Intermolecular forces: Van der Waals, dipole - dipole, and hydrogen bonds (\(H\) is bonded to highly electronegative \(F\)).
- For \(H_{2}O\):
- Lewis structure: Oxygen (6 valence electrons) is the central atom. It forms two \(O - H\) bonds (each \(H\) has 1 valence electron). There are two lone pairs on oxygen. The structure is bent.
- Polar bonds: \(O - H\) bonds are polar (\(O(3.5)-H(2.1)=1.4\)).
- Molecular polarity: Polar (bent shape causes asymmetry).
- Intermolecular forces: Van der Waals, dipole - dipole, and hydrogen bonds (\(H\) is bonded to highly electronegative \(O\)).
- For \(CH_{3}Cl\):
- Lewis structure: Carbon is the central atom. It forms three \(C - H\) bonds (\(H\) has 1 valence electron) and one \(C - Cl\) bond (\(Cl\) has 7 valence electrons). The structure is tetrahedral (asymmetrical due to \(Cl\)).
- Polar bonds: \(C - Cl\) bond is polar (\(Cl(3.0)-C(2.5)=0.5\)), \(C - H\) bonds are slightly polar (\(C(2.5)-H(2.1)=0.4\)).
- Molecular polarity: Polar.
- Intermolecular forces: Van der Waals, dipole - dipole.
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| Molecule | Lewis structure | Does it contain polar bonds? | Is the molecule polar? | Intermolecular Forces present |
|---|---|---|---|---|
| \(F_{2}\) | \(F - F\) single bond | No | No | Van der Waals (\(\checkmark\)) |
| \(BF_{3}\) | Central \(B\) with three \(B - F\) bonds (trigonal planar) | Yes | No | Van der Waals (\(\checkmark\)) |
| \(CCl_{4}\) | Central \(C\) with four \(C - Cl\) bonds (tetrahedral) | Yes | No | Van der Waals (\(\checkmark\)) |
| \(HF\) | \(H - F\) single bond | Yes | Yes | Van der Waals (\(\checkmark\)), Dipole - dipole (\(\checkmark\)), Hydrogen bonds (\(\checkmark\)) |
| \(H_{2}O\) | Central \(O\) with two \(O - H\) bonds and two lone pairs (bent) | Yes | Yes | Van der Waals (\(\checkmark\)), Dipole - dipole (\(\checkmark\)), Hydrogen bonds (\(\checkmark\)) |
| \(CH_{3}Cl\) | Central \(C\) with three \(C - H\) and one \(C - Cl\) bond (asymmetric tetrahedral) | Yes | Yes | Van der Waals (\(\checkmark\)), Dipole - dipole (\(\checkmark\)) |